(x+1)(2x+3)(x-1)(2x-1)=63

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Solution for (x+1)(2x+3)(x-1)(2x-1)=63 equation: 



(x+1)(2x+3)(x-1)(2x-1)=63

We move all terms to the left:

(x+1)(2x+3)(x-1)(2x-1)-(63)=0

We multiply parentheses ..

(+2x^2+3x+2x+3)(x-1)(2x-1)-63=0

We multiply parentheses ..

(+2x^2+3x+2x+3)(+2x^2-1x-2x+1)-63=0

We move all terms containing x to the left, all other terms to the right

(+2x^2+3x+2x+3)(+2x^2-1x-2x+1)=63

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