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(x+1)(4x+7)=0
We multiply parentheses ..
(+4x^2+7x+4x+7)=0
We get rid of parentheses
4x^2+7x+4x+7=0
We add all the numbers together, and all the variables
4x^2+11x+7=0
a = 4; b = 11; c = +7;
Δ = b2-4ac
Δ = 112-4·4·7
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-3}{2*4}=\frac{-14}{8} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+3}{2*4}=\frac{-8}{8} =-1 $
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