(x+1)(x+1)(x+(3+2I)(x+(3-2I)=0

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Solution for (x+1)(x+1)(x+(3+2I)(x+(3-2I)=0 equation: 



(x+1)(x+1)(x+(3+2)(x+(3-2)=0

We add all the numbers together, and all the variables

(x+1)(x+1)(x+5(x+1=0

We multiply parentheses ..

(+x^2+x+x+1)(x+5(x+1=0

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