(x+1)(x+1)+16=0

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Solution for (x+1)(x+1)+16=0 equation:


Simplifying
(x + 1)(x + 1) + 16 = 0

Reorder the terms:
(1 + x)(x + 1) + 16 = 0

Reorder the terms:
(1 + x)(1 + x) + 16 = 0

Multiply (1 + x) * (1 + x)
(1(1 + x) + x(1 + x)) + 16 = 0
((1 * 1 + x * 1) + x(1 + x)) + 16 = 0
((1 + 1x) + x(1 + x)) + 16 = 0
(1 + 1x + (1 * x + x * x)) + 16 = 0
(1 + 1x + (1x + x2)) + 16 = 0

Combine like terms: 1x + 1x = 2x
(1 + 2x + x2) + 16 = 0

Reorder the terms:
1 + 16 + 2x + x2 = 0

Combine like terms: 1 + 16 = 17
17 + 2x + x2 = 0

Solving
17 + 2x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-17' to each side of the equation.
17 + 2x + -17 + x2 = 0 + -17

Reorder the terms:
17 + -17 + 2x + x2 = 0 + -17

Combine like terms: 17 + -17 = 0
0 + 2x + x2 = 0 + -17
2x + x2 = 0 + -17

Combine like terms: 0 + -17 = -17
2x + x2 = -17

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -17 + 1

Reorder the terms:
1 + 2x + x2 = -17 + 1

Combine like terms: -17 + 1 = -16
1 + 2x + x2 = -16

Factor a perfect square on the left side:
(x + 1)(x + 1) = -16

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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