(x+1)(x+1)=xxx+29

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Solution for (x+1)(x+1)=xxx+29 equation: 



(x+1)(x+1)=xxx+29

We move all terms to the left:

(x+1)(x+1)-(xxx+29)=0

We get rid of parentheses

(x+1)(x+1)-xxx-29=0

We multiply parentheses ..

(+x^2+x+x+1)-xxx-29=0

We get rid of parentheses

x^2+x+x-xxx+1-29=0

We add all the numbers together, and all the variables

x^2+2x-xxx-28=0

We move all terms containing x to the left, all other terms to the right

x^2+2x-xxx=28

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