(x+1)(x+11)=924

Solution for (x+1)(x+11)=924 equation:

(x+1)(x+11)=924

We move all terms to the left:

(x+1)(x+11)-(924)=0

We multiply parentheses ..

(+x^2+11x+x+11)-924=0

We get rid of parentheses

x^2+11x+x+11-924=0

We add all the numbers together, and all the variables

x^2+12x-913=0

a = 1; b = 12; c = -913;
Δ = b2-4ac
Δ = 122-4·1·(-913)
Δ = 3796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3796}=\sqrt{4*949}=\sqrt{4}*\sqrt{949}=2\sqrt{949}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{949}}{2*1}=\frac{-12-2\sqrt{949}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{949}}{2*1}=\frac{-12+2\sqrt{949}}{2}
$