(x+1)(x+12)(x-3)=0

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Solution for (x+1)(x+12)(x-3)=0 equation:


Simplifying
(x + 1)(x + 12)(x + -3) = 0

Reorder the terms:
(1 + x)(x + 12)(x + -3) = 0

Reorder the terms:
(1 + x)(12 + x)(x + -3) = 0

Reorder the terms:
(1 + x)(12 + x)(-3 + x) = 0

Multiply (1 + x) * (12 + x)
(1(12 + x) + x(12 + x))(-3 + x) = 0
((12 * 1 + x * 1) + x(12 + x))(-3 + x) = 0
((12 + 1x) + x(12 + x))(-3 + x) = 0
(12 + 1x + (12 * x + x * x))(-3 + x) = 0
(12 + 1x + (12x + x2))(-3 + x) = 0

Combine like terms: 1x + 12x = 13x
(12 + 13x + x2)(-3 + x) = 0

Multiply (12 + 13x + x2) * (-3 + x)
(12(-3 + x) + 13x * (-3 + x) + x2(-3 + x)) = 0
((-3 * 12 + x * 12) + 13x * (-3 + x) + x2(-3 + x)) = 0
((-36 + 12x) + 13x * (-3 + x) + x2(-3 + x)) = 0
(-36 + 12x + (-3 * 13x + x * 13x) + x2(-3 + x)) = 0
(-36 + 12x + (-39x + 13x2) + x2(-3 + x)) = 0
(-36 + 12x + -39x + 13x2 + (-3 * x2 + x * x2)) = 0
(-36 + 12x + -39x + 13x2 + (-3x2 + x3)) = 0

Combine like terms: 12x + -39x = -27x
(-36 + -27x + 13x2 + -3x2 + x3) = 0

Combine like terms: 13x2 + -3x2 = 10x2
(-36 + -27x + 10x2 + x3) = 0

Solving
-36 + -27x + 10x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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