(x+1)(x+14)=(x+14)(x-20)

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Solution for (x+1)(x+14)=(x+14)(x-20) equation:



(x+1)(x+14)=(x+14)(x-20)
We move all terms to the left:
(x+1)(x+14)-((x+14)(x-20))=0
We multiply parentheses ..
(+x^2+14x+x+14)-((x+14)(x-20))=0
We calculate terms in parentheses: -((x+14)(x-20)), so:
(x+14)(x-20)
We multiply parentheses ..
(+x^2-20x+14x-280)
We get rid of parentheses
x^2-20x+14x-280
We add all the numbers together, and all the variables
x^2-6x-280
Back to the equation:
-(x^2-6x-280)
We get rid of parentheses
x^2-x^2+14x+x+6x+14+280=0
We add all the numbers together, and all the variables
21x+294=0
We move all terms containing x to the left, all other terms to the right
21x=-294
x=-294/21
x=-14

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