(x+1)(x+2)(x+3)(x+4)=4

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Solution for (x+1)(x+2)(x+3)(x+4)=4 equation: 



(x+1)(x+2)(x+3)(x+4)=4

We move all terms to the left:

(x+1)(x+2)(x+3)(x+4)-(4)=0

We multiply parentheses ..

(+x^2+2x+x+2)(x+3)(x+4)-4=0

We multiply parentheses ..

(+x^2+2x+x+2)(+x^2+4x+3x+12)-4=0

We move all terms containing x to the left, all other terms to the right

(+x^2+2x+x+2)(+x^2+4x+3x+12)=4

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