(x+1)(x+2)-2=x(x+3)

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Solution for (x+1)(x+2)-2=x(x+3) equation:


Simplifying
(x + 1)(x + 2) + -2 = x(x + 3)

Reorder the terms:
(1 + x)(x + 2) + -2 = x(x + 3)

Reorder the terms:
(1 + x)(2 + x) + -2 = x(x + 3)

Multiply (1 + x) * (2 + x)
(1(2 + x) + x(2 + x)) + -2 = x(x + 3)
((2 * 1 + x * 1) + x(2 + x)) + -2 = x(x + 3)
((2 + 1x) + x(2 + x)) + -2 = x(x + 3)
(2 + 1x + (2 * x + x * x)) + -2 = x(x + 3)
(2 + 1x + (2x + x2)) + -2 = x(x + 3)

Combine like terms: 1x + 2x = 3x
(2 + 3x + x2) + -2 = x(x + 3)

Reorder the terms:
2 + -2 + 3x + x2 = x(x + 3)

Combine like terms: 2 + -2 = 0
0 + 3x + x2 = x(x + 3)
3x + x2 = x(x + 3)

Reorder the terms:
3x + x2 = x(3 + x)
3x + x2 = (3 * x + x * x)
3x + x2 = (3x + x2)

Add '-3x' to each side of the equation.
3x + -3x + x2 = 3x + -3x + x2

Combine like terms: 3x + -3x = 0
0 + x2 = 3x + -3x + x2
x2 = 3x + -3x + x2

Combine like terms: 3x + -3x = 0
x2 = 0 + x2
x2 = x2

Add '-1x2' to each side of the equation.
x2 + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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