(x+1)(x+2)=(x-5)(x-6

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Solution for (x+1)(x+2)=(x-5)(x-6 equation: 



(x+1)(x+2)=(x-5)(x-6

We move all terms to the left:

(x+1)(x+2)-((x-5)(x-6)=0

We multiply parentheses ..

(+x^2+2x+x+2)-((x-5)(x-6)=0



We calculate terms in parentheses: -((x-5)(x-6), so:

(x-5)(x-6



We get rid of parentheses

x^2+2x+x-((x-5)(x-6)+2=0

We multiply parentheses ..

x^2-((+x^2-6x-5x+30)+2+2x+x=0

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