(x+1)(x+4)=(x+2)(x+5)

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Solution for (x+1)(x+4)=(x+2)(x+5) equation: 



(x+1)(x+4)=(x+2)(x+5)

We move all terms to the left:

(x+1)(x+4)-((x+2)(x+5))=0

We multiply parentheses ..

(+x^2+4x+x+4)-((x+2)(x+5))=0



We calculate terms in parentheses: -((x+2)(x+5)), so:

(x+2)(x+5)

We multiply parentheses ..

(+x^2+5x+2x+10)

We get rid of parentheses

x^2+5x+2x+10

We add all the numbers together, and all the variables

x^2+7x+10

Back to the equation:

-(x^2+7x+10)



We get rid of parentheses

x^2-x^2+4x+x-7x+4-10=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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