(x+1)(x+5)=480

Solution for (x+1)(x+5)=480 equation:

(x+1)(x+5)=480

We move all terms to the left:

(x+1)(x+5)-(480)=0

We multiply parentheses ..

(+x^2+5x+x+5)-480=0

We get rid of parentheses

x^2+5x+x+5-480=0

We add all the numbers together, and all the variables

x^2+6x-475=0

a = 1; b = 6; c = -475;
Δ = b2-4ac
Δ = 62-4·1·(-475)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-44}{2*1}=\frac{-50}{2}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+44}{2*1}=\frac{38}{2}
=19
$