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(x+1)(x-1)-x2=x+3
We move all terms to the left:
(x+1)(x-1)-x2-(x+3)=0
We add all the numbers together, and all the variables
-1x^2+(x+1)(x-1)-(x+3)=0
We use the square of the difference formula
-1x^2+x^2-(x+3)-1=0
We get rid of parentheses
-1x^2+x^2-x-3-1=0
We add all the numbers together, and all the variables
-1x-4=0
We move all terms containing x to the left, all other terms to the right
-x=4
x=4/-1
x=-4
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