(x+1)(x-1)=(x+5)(x+3)

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Solution for (x+1)(x-1)=(x+5)(x+3) equation: 



(x+1)(x-1)=(x+5)(x+3)

We move all terms to the left:

(x+1)(x-1)-((x+5)(x+3))=0

We use the square of the difference formula

x^2-((x+5)(x+3))-1=0

We multiply parentheses ..

x^2-((+x^2+3x+5x+15))-1=0



We calculate terms in parentheses: -((+x^2+3x+5x+15)), so:

(+x^2+3x+5x+15)

We get rid of parentheses

x^2+3x+5x+15

We add all the numbers together, and all the variables

x^2+8x+15

Back to the equation:

-(x^2+8x+15)



We get rid of parentheses

x^2-x^2-8x-15-1=0

We add all the numbers together, and all the variables

-8x-16=0

We move all terms containing x to the left, all other terms to the right

-8x=16

x=16/-8

x=-2

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