(x+1)(x-1)=x(x+1)-(x+1)

Solution for (x+1)(x-1)=x(x+1)-(x+1) equation:

(x+1)(x-1)=x(x+1)-(x+1)

We move all terms to the left:

(x+1)(x-1)-(x(x+1)-(x+1))=0

We use the square of the difference formula

x^2-(x(x+1)-(x+1))-1=0


We calculate terms in parentheses: -(x(x+1)-(x+1)), so:

x(x+1)-(x+1)

We multiply parentheses

x^2+x-(x+1)

We get rid of parentheses

x^2+x-x-1

We add all the numbers together, and all the variables

x^2-1

Back to the equation:

-(x^2-1)


We get rid of parentheses

x^2-x^2+1-1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0