(x+1)(x-1)=x(x+1)-(x-1)

Solution for (x+1)(x-1)=x(x+1)-(x-1) equation:

(x+1)(x-1)=x(x+1)-(x-1)

We move all terms to the left:

(x+1)(x-1)-(x(x+1)-(x-1))=0

We use the square of the difference formula

x^2-(x(x+1)-(x-1))-1=0


We calculate terms in parentheses: -(x(x+1)-(x-1)), so:

x(x+1)-(x-1)

We multiply parentheses

x^2+x-(x-1)

We get rid of parentheses

x^2+x-x+1

We add all the numbers together, and all the variables

x^2+1

Back to the equation:

-(x^2+1)


We get rid of parentheses

x^2-x^2-1-1=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation