(x+1)(x-2)(x+3)(x+4)=99

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Solution for (x+1)(x-2)(x+3)(x+4)=99 equation: 



(x+1)(x-2)(x+3)(x+4)=99

We move all terms to the left:

(x+1)(x-2)(x+3)(x+4)-(99)=0

We multiply parentheses ..

(+x^2-2x+x-2)(x+3)(x+4)-99=0

We multiply parentheses ..

(+x^2-2x+x-2)(+x^2+4x+3x+12)-99=0

We move all terms containing x to the left, all other terms to the right

(+x^2-2x+x-2)(+x^2+4x+3x+12)=99

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