(x+1)(x-2)-(x+5)(x+4)=-2

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Solution for (x+1)(x-2)-(x+5)(x+4)=-2 equation: 



(x+1)(x-2)-(x+5)(x+4)=-2

We move all terms to the left:

(x+1)(x-2)-(x+5)(x+4)-(-2)=0

We add all the numbers together, and all the variables

(x+1)(x-2)-(x+5)(x+4)+2=0

We multiply parentheses ..

(+x^2-2x+x-2)-(x+5)(x+4)+2=0

We get rid of parentheses

x^2-2x+x-(x+5)(x+4)-2+2=0

We multiply parentheses ..

x^2-(+x^2+4x+5x+20)-2x+x-2+2=0

We add all the numbers together, and all the variables

x^2-(+x^2+4x+5x+20)-1x=0

We get rid of parentheses

x^2-x^2-4x-5x-1x-20=0

We add all the numbers together, and all the variables

-10x-20=0

We move all terms containing x to the left, all other terms to the right

-10x=20

x=20/-10

x=-2

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