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D( x )
x-3 = 0
x+1 = 0
x-3 = 0
x-3 = 0
x-3 = 0 // + 3
x = 3
x+1 = 0
x+1 = 0
x+1 = 0 // - 1
x = -1
x in (-oo:-1) U (-1:3) U (3:+oo)
(((((x+1)*(x-3))/(x+1))*(x-1)*(5*x-5))/(x-3))*(x-1) = 0
(x-1)^2*(5*x-5) = 0
( 5*x-5 )
5*x-5 = 0 // + 5
5*x = 5 // : 5
x = 5/5
x = 1
( x-1 )
x-1 = 0 // + 1
x = 1
x in { 1, 1, 1 }
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