(x+1)(x-4)+3x=0

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Solution for (x+1)(x-4)+3x=0 equation:


Simplifying
(x + 1)(x + -4) + 3x = 0

Reorder the terms:
(1 + x)(x + -4) + 3x = 0

Reorder the terms:
(1 + x)(-4 + x) + 3x = 0

Multiply (1 + x) * (-4 + x)
(1(-4 + x) + x(-4 + x)) + 3x = 0
((-4 * 1 + x * 1) + x(-4 + x)) + 3x = 0
((-4 + 1x) + x(-4 + x)) + 3x = 0
(-4 + 1x + (-4 * x + x * x)) + 3x = 0
(-4 + 1x + (-4x + x2)) + 3x = 0

Combine like terms: 1x + -4x = -3x
(-4 + -3x + x2) + 3x = 0

Reorder the terms:
-4 + -3x + 3x + x2 = 0

Combine like terms: -3x + 3x = 0
-4 + 0 + x2 = 0
-4 + x2 = 0

Solving
-4 + x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + x2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + x2 = 0 + 4
x2 = 0 + 4

Combine like terms: 0 + 4 = 4
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}

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