(x+1)(x-4)+7=x(-2)-1

Solution for (x+1)(x-4)+7=x(-2)-1 equation:

(x+1)(x-4)+7=x(-2)-1

We move all terms to the left:

(x+1)(x-4)+7-(x(-2)-1)=0

We multiply parentheses ..

(+x^2-4x+x-4)-(x(-2)-1)+7=0


We calculate terms in parentheses: -(x(-2)-1), so:

x(-2)-1

We multiply parentheses

-2x-1

Back to the equation:

-(-2x-1)


We get rid of parentheses

x^2-4x+x+2x-4+1+7=0

We add all the numbers together, and all the variables

x^2-1x+4=0

a = 1; b = -1; c = +4;
Δ = b2-4ac
Δ = -12-4·1·4
Δ = -15
Delta is less than zero, so there is no solution for the equation