(x+1)(x-4)=(x-2)(x-2)

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Solution for (x+1)(x-4)=(x-2)(x-2) equation: 



(x+1)(x-4)=(x-2)(x-2)

We move all terms to the left:

(x+1)(x-4)-((x-2)(x-2))=0

We multiply parentheses ..

(+x^2-4x+x-4)-((x-2)(x-2))=0



We calculate terms in parentheses: -((x-2)(x-2)), so:

(x-2)(x-2)

We multiply parentheses ..

(+x^2-2x-2x+4)

We get rid of parentheses

x^2-2x-2x+4

We add all the numbers together, and all the variables

x^2-4x+4

Back to the equation:

-(x^2-4x+4)



We get rid of parentheses

x^2-x^2-4x+x+4x-4-4=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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