(x+1)+(3x-5)+(2x-1)=36

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Solution for (x+1)+(3x-5)+(2x-1)=36 equation: 



(x+1)+(3x-5)+(2x-1)=36

We move all terms to the left:

(x+1)+(3x-5)+(2x-1)-(36)=0

We get rid of parentheses

x+3x+2x+1-5-1-36=0

We add all the numbers together, and all the variables

6x-41=0

We move all terms containing x to the left, all other terms to the right

6x=41

x=41/6

x=6+5/6

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