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(x+1)+(x+2)=(2x+1)+x+2
We move all terms to the left:
(x+1)+(x+2)-((2x+1)+x+2)=0
We get rid of parentheses
x+x-((2x+1)+x+2)+1+2=0
We calculate terms in parentheses: -((2x+1)+x+2), so:We add all the numbers together, and all the variables
(2x+1)+x+2
We add all the numbers together, and all the variables
x+(2x+1)+2
We get rid of parentheses
x+2x+1+2
We add all the numbers together, and all the variables
3x+3
Back to the equation:
-(3x+3)
2x-(3x+3)+3=0
We get rid of parentheses
2x-3x-3+3=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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