(x+1)+(x+2)+(x+3)=147

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Solution for (x+1)+(x+2)+(x+3)=147 equation: 



(x+1)+(x+2)+(x+3)=147

We move all terms to the left:

(x+1)+(x+2)+(x+3)-(147)=0

We get rid of parentheses

x+x+x+1+2+3-147=0

We add all the numbers together, and all the variables

3x-141=0

We move all terms containing x to the left, all other terms to the right

3x=141

x=141/3

x=47

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