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(x+1)+(x+2)+x=(2x+1)+x
We move all terms to the left:
(x+1)+(x+2)+x-((2x+1)+x)=0
We add all the numbers together, and all the variables
x+(x+1)+(x+2)-((2x+1)+x)=0
We get rid of parentheses
x+x+x-((2x+1)+x)+1+2=0
We calculate terms in parentheses: -((2x+1)+x), so:We add all the numbers together, and all the variables
(2x+1)+x
We add all the numbers together, and all the variables
x+(2x+1)
We get rid of parentheses
x+2x+1
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
3x-(3x+1)+3=0
We get rid of parentheses
3x-3x-1+3=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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