(x+1)+(x+3)=2(x+3)-2

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Solution for (x+1)+(x+3)=2(x+3)-2 equation:


Simplifying
(x + 1) + (x + 3) = 2(x + 3) + -2

Reorder the terms:
(1 + x) + (x + 3) = 2(x + 3) + -2

Remove parenthesis around (1 + x)
1 + x + (x + 3) = 2(x + 3) + -2

Reorder the terms:
1 + x + (3 + x) = 2(x + 3) + -2

Remove parenthesis around (3 + x)
1 + x + 3 + x = 2(x + 3) + -2

Reorder the terms:
1 + 3 + x + x = 2(x + 3) + -2

Combine like terms: 1 + 3 = 4
4 + x + x = 2(x + 3) + -2

Combine like terms: x + x = 2x
4 + 2x = 2(x + 3) + -2

Reorder the terms:
4 + 2x = 2(3 + x) + -2
4 + 2x = (3 * 2 + x * 2) + -2
4 + 2x = (6 + 2x) + -2

Reorder the terms:
4 + 2x = 6 + -2 + 2x

Combine like terms: 6 + -2 = 4
4 + 2x = 4 + 2x

Add '-4' to each side of the equation.
4 + -4 + 2x = 4 + -4 + 2x

Combine like terms: 4 + -4 = 0
0 + 2x = 4 + -4 + 2x
2x = 4 + -4 + 2x

Combine like terms: 4 + -4 = 0
2x = 0 + 2x
2x = 2x

Add '-2x' to each side of the equation.
2x + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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