(x+1)+(x-2)-(x+3)=0

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Solution for (x+1)+(x-2)-(x+3)=0 equation:


Simplifying
(x + 1) + (x + -2) + -1(x + 3) = 0

Reorder the terms:
(1 + x) + (x + -2) + -1(x + 3) = 0

Remove parenthesis around (1 + x)
1 + x + (x + -2) + -1(x + 3) = 0

Reorder the terms:
1 + x + (-2 + x) + -1(x + 3) = 0

Remove parenthesis around (-2 + x)
1 + x + -2 + x + -1(x + 3) = 0

Reorder the terms:
1 + x + -2 + x + -1(3 + x) = 0
1 + x + -2 + x + (3 * -1 + x * -1) = 0
1 + x + -2 + x + (-3 + -1x) = 0

Reorder the terms:
1 + -2 + -3 + x + x + -1x = 0

Combine like terms: 1 + -2 = -1
-1 + -3 + x + x + -1x = 0

Combine like terms: -1 + -3 = -4
-4 + x + x + -1x = 0

Combine like terms: x + x = 2x
-4 + 2x + -1x = 0

Combine like terms: 2x + -1x = 1x
-4 + 1x = 0

Solving
-4 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 1x = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 1x = 0 + 4
1x = 0 + 4

Combine like terms: 0 + 4 = 4
1x = 4

Divide each side by '1'.
x = 4

Simplifying
x = 4

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