(x+1)+3x=26+(x+2)

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Solution for (x+1)+3x=26+(x+2) equation: 



(x+1)+3x=26+(x+2)

We move all terms to the left:

(x+1)+3x-(26+(x+2))=0

We add all the numbers together, and all the variables

3x+(x+1)-(26+(x+2))=0

We get rid of parentheses

3x+x-(26+(x+2))+1=0



We calculate terms in parentheses: -(26+(x+2)), so:

26+(x+2)

determiningTheFunctionDomain
(x+2)+26

We get rid of parentheses

x+2+26

We add all the numbers together, and all the variables

x+28

Back to the equation:

-(x+28)



We add all the numbers together, and all the variables

4x-(x+28)+1=0

We get rid of parentheses

4x-x-28+1=0

We add all the numbers together, and all the variables

3x-27=0

We move all terms containing x to the left, all other terms to the right

3x=27

x=27/3

x=9

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