(x+1)+log(x-4)=2

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Solution for (x+1)+log(x-4)=2 equation:


Simplifying
(x + 1) + log(x + -4) = 2

Reorder the terms:
(1 + x) + log(x + -4) = 2

Remove parenthesis around (1 + x)
1 + x + log(x + -4) = 2

Reorder the terms:
1 + x + glo(-4 + x) = 2
1 + x + (-4 * glo + x * glo) = 2
1 + x + (-4glo + glox) = 2

Reorder the terms:
1 + -4glo + glox + x = 2

Solving
1 + -4glo + glox + x = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -4glo + glox + -1 + x = 2 + -1

Reorder the terms:
1 + -1 + -4glo + glox + x = 2 + -1

Combine like terms: 1 + -1 = 0
0 + -4glo + glox + x = 2 + -1
-4glo + glox + x = 2 + -1

Combine like terms: 2 + -1 = 1
-4glo + glox + x = 1

Add '-1x' to each side of the equation.
-4glo + glox + x + -1x = 1 + -1x

Combine like terms: x + -1x = 0
-4glo + glox + 0 = 1 + -1x
-4glo + glox = 1 + -1x

Reorder the terms:
-1 + -4glo + glox + x = 1 + -1x + -1 + x

Reorder the terms:
-1 + -4glo + glox + x = 1 + -1 + -1x + x

Combine like terms: 1 + -1 = 0
-1 + -4glo + glox + x = 0 + -1x + x
-1 + -4glo + glox + x = -1x + x

Combine like terms: -1x + x = 0
-1 + -4glo + glox + x = 0

The solution to this equation could not be determined.

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