(x+1)-(x-2)-(x-3)=3

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Solution for (x+1)-(x-2)-(x-3)=3 equation:


Simplifying
(x + 1) + -1(x + -2) + -1(x + -3) = 3

Reorder the terms:
(1 + x) + -1(x + -2) + -1(x + -3) = 3

Remove parenthesis around (1 + x)
1 + x + -1(x + -2) + -1(x + -3) = 3

Reorder the terms:
1 + x + -1(-2 + x) + -1(x + -3) = 3
1 + x + (-2 * -1 + x * -1) + -1(x + -3) = 3
1 + x + (2 + -1x) + -1(x + -3) = 3

Reorder the terms:
1 + x + 2 + -1x + -1(-3 + x) = 3
1 + x + 2 + -1x + (-3 * -1 + x * -1) = 3
1 + x + 2 + -1x + (3 + -1x) = 3

Reorder the terms:
1 + 2 + 3 + x + -1x + -1x = 3

Combine like terms: 1 + 2 = 3
3 + 3 + x + -1x + -1x = 3

Combine like terms: 3 + 3 = 6
6 + x + -1x + -1x = 3

Combine like terms: x + -1x = 0
6 + 0 + -1x = 3
6 + -1x = 3

Solving
6 + -1x = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1x = 3 + -6

Combine like terms: 6 + -6 = 0
0 + -1x = 3 + -6
-1x = 3 + -6

Combine like terms: 3 + -6 = -3
-1x = -3

Divide each side by '-1'.
x = 3

Simplifying
x = 3

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