If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(x+1)/(2x)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
(x+1)=0
We get rid of parentheses
x+1=0
We move all terms containing x to the left, all other terms to the right
x=-1
| 5x-4=6x-15 | | a+2(a-3)=20 | | -3u+7(u+2)=18 | | -66=-6k | | 1d-15.6=2d-556.3 | | |4x-9|=13 | | 3x-8+10=10 | | q=-18.4+(28.7) | | 0.2=x+1.5 | | -X^2+6.5x-30=0 | | -22-7x=-4(9x+5) | | -7=11+9p | | 3y+2y-4+6=7 | | -2g+4=-6g-9 | | 5c-4=-14 | | 2x-3x/4=4 | | 9/n=8/11 | | 8*(x+0.5)=44 | | 7f+2f=-16 | | 5y+18=13 | | -3y-6=-21 | | -9d-4(-3d-3)=6d+6+6d | | -1+1x=-8 | | 8*(x+0.5=44 | | 18a=+12+9+24 | | (x+20)(x+3)=x^2-10 | | 4(x−6)=7(x−9) | | 250=7+50x | | -28+3m=-23 | | 9x-7=x+113 | | 8−4z=2z−16 | | 5(10x)+3=808 |