(x+1)/(x-1)=(3x-6)/(3x-6)

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Solution for (x+1)/(x-1)=(3x-6)/(3x-6) equation: 


D( x )

3*x-6 = 0

x-1 = 0

3*x-6 = 0

3*x-6 = 0

3*x-6 = 0 // + 6

3*x = 6 // : 3

x = 6/3

x = 2

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:2) U (2:+oo)

(x+1)/(x-1) = (3*x-6)/(3*x-6) // - (3*x-6)/(3*x-6)

(x+1)/(x-1)-((3*x-6)/(3*x-6)) = 0

(x+1)/(x-1)-1 = 0

(x+1)/(x-1)+(-1*(x-1))/(x-1) = 0

x-1*(x-1)+1 = 0

2 = 0

2/(x-1) = 0

2/(x-1) = 0 // * x-1

2 = 0

x belongs to the empty set

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