(x+1)/(x-4)=1

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Solution for (x+1)/(x-4)=1 equation: 


D( x )

x-4 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

(x+1)/(x-4) = 1 // - 1

(x+1)/(x-4)-1 = 0

(x+1)/(x-4)+(-1*(x-4))/(x-4) = 0

x-1*(x-4)+1 = 0

5 = 0

5/(x-4) = 0

5/(x-4) = 0 // * x-4

5 = 0

x belongs to the empty set

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