(x+1)/2+(x+2)/3+(x-6)/6=x/18

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Solution for (x+1)/2+(x+2)/3+(x-6)/6=x/18 equation: 



(x+1)/2+(x+2)/3+(x-6)/6=x/18

We move all terms to the left:

(x+1)/2+(x+2)/3+(x-6)/6-(x/18)=0

We add all the numbers together, and all the variables

(x+1)/2+(x+2)/3+(x-6)/6-(+x/18)=0

We get rid of parentheses

(x+1)/2+(x+2)/3+(x-6)/6-x/18=0

We calculate fractions

There is no solution for this equation

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