(x+1)/2=(3x+7)/5

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Solution for (x+1)/2=(3x+7)/5 equation: 



(x+1)/2=(3x+7)/5

We move all terms to the left:

(x+1)/2-((3x+7)/5)=0

We calculate fractions


x/()+(-((3x+7)*2)/()=0



We calculate terms in parentheses: +(-((3x+7)*2)/(), so:

-((3x+7)*2)/(

We multiply all the terms by the denominator


-((3x+7)*2)



We calculate terms in parentheses: -((3x+7)*2), so:

(3x+7)*2

We multiply parentheses

6x+14

Back to the equation:

-(6x+14)



We get rid of parentheses

-6x-14

Back to the equation:

+(-6x-14)



We get rid of parentheses

x/()-6x-14=0

We multiply all the terms by the denominator


x-6x*()-14*()=0

We add all the numbers together, and all the variables

x-6x*()=0

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