(x+1)/2=1-(x+2)/5

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Solution for (x+1)/2=1-(x+2)/5 equation: 



(x+1)/2=1-(x+2)/5

We move all terms to the left:

(x+1)/2-(1-(x+2)/5)=0

We calculate fractions


x/()+(-(1-(x+2)*2)/()=0



We calculate terms in parentheses: +(-(1-(x+2)*2)/(), so:

-(1-(x+2)*2)/(

We multiply all the terms by the denominator


-(1-(x+2)*2)



We calculate terms in parentheses: -(1-(x+2)*2), so:

1-(x+2)*2

determiningTheFunctionDomain
-(x+2)*2+1

We multiply parentheses

-2x-4+1

We add all the numbers together, and all the variables

-2x-3

Back to the equation:

-(-2x-3)



We get rid of parentheses

2x+3

Back to the equation:

+(2x+3)



We get rid of parentheses

x/()+2x+3=0

We multiply all the terms by the denominator


x+2x*()+3*()=0

We add all the numbers together, and all the variables

x+2x*()=0

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