(x+1)/2=3-(x+4)/7

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Solution for (x+1)/2=3-(x+4)/7 equation: 



(x+1)/2=3-(x+4)/7

We move all terms to the left:

(x+1)/2-(3-(x+4)/7)=0

We calculate fractions


x/()+(-(3-(x+4)*2)/()=0



We calculate terms in parentheses: +(-(3-(x+4)*2)/(), so:

-(3-(x+4)*2)/(

We multiply all the terms by the denominator


-(3-(x+4)*2)



We calculate terms in parentheses: -(3-(x+4)*2), so:

3-(x+4)*2

determiningTheFunctionDomain
-(x+4)*2+3

We multiply parentheses

-2x-8+3

We add all the numbers together, and all the variables

-2x-5

Back to the equation:

-(-2x-5)



We get rid of parentheses

2x+5

Back to the equation:

+(2x+5)



We get rid of parentheses

x/()+2x+5=0

We multiply all the terms by the denominator


x+2x*()+5*()=0

We add all the numbers together, and all the variables

x+2x*()=0

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