(x+1)/3+(2x-1)/4=(10x+1)/12

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Solution for (x+1)/3+(2x-1)/4=(10x+1)/12 equation: 


x in (-oo:+oo)

(x+1)/3+(2*x-1)/4 = (10*x+1)/12 // - (10*x+1)/12

(x+1)/3+(2*x-1)/4-((10*x+1)/12) = 0

(x+1)/3+(2*x-1)/4+(-1*(10*x+1))/12 = 0

(4*12*(x+1))/(3*4*12)+(3*12*(2*x-1))/(3*4*12)+(-1*3*4*(10*x+1))/(3*4*12) = 0

4*12*(x+1)+3*12*(2*x-1)-1*3*4*(10*x+1) = 0

120*x-120*x-12+12 = 0

0 = 0

0/(3*4*12) = 0

0/(3*4*12) = 0 // * 3*4*12

0 = 0

x belongs to the empty set

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