(x+1)/3=(2x+2)/6

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Solution for (x+1)/3=(2x+2)/6 equation: 


x in (-oo:+oo)

(x+1)/3 = (2*x+2)/6 // - (2*x+2)/6

(x+1)/3-((2*x+2)/6) = 0

(x+1)/3+(-1*(2*x+2))/6 = 0

(6*(x+1))/(3*6)+(-1*3*(2*x+2))/(3*6) = 0

6*(x+1)-1*3*(2*x+2) = 0

0 = 0

0/(3*6) = 0

0/(3*6) = 0 // * 3*6

0 = 0

x belongs to the empty set

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