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(x+1)/3=2x-13
We move all terms to the left:
(x+1)/3-(2x-13)=0
We get rid of parentheses
(x+1)/3-2x+13=0
We multiply all the terms by the denominator
(x+1)-2x*3+13*3=0
We add all the numbers together, and all the variables
(x+1)-2x*3+39=0
Wy multiply elements
(x+1)-6x+39=0
We get rid of parentheses
x-6x+1+39=0
We add all the numbers together, and all the variables
-5x+40=0
We move all terms containing x to the left, all other terms to the right
-5x=-40
x=-40/-5
x=+8
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