(x+1)/4=(8-x)/5

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Solution for (x+1)/4=(8-x)/5 equation: 



(x+1)/4=(8-x)/5

We move all terms to the left:

(x+1)/4-((8-x)/5)=0

We add all the numbers together, and all the variables

(x+1)/4-((-1x+8)/5)=0

We calculate fractions


x/()+(-((-1x+8)*4)/()=0



We calculate terms in parentheses: +(-((-1x+8)*4)/(), so:

-((-1x+8)*4)/(

We multiply all the terms by the denominator


-((-1x+8)*4)



We calculate terms in parentheses: -((-1x+8)*4), so:

(-1x+8)*4

We multiply parentheses

-4x+32

Back to the equation:

-(-4x+32)



We get rid of parentheses

4x-32

Back to the equation:

+(4x-32)



We get rid of parentheses

x/()+4x-32=0

We multiply all the terms by the denominator


x+4x*()-32*()=0

We add all the numbers together, and all the variables

x+4x*()=0

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