(x+1)/5=(x+5)/7

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Solution for (x+1)/5=(x+5)/7 equation: 



(x+1)/5=(x+5)/7

We move all terms to the left:

(x+1)/5-((x+5)/7)=0

We calculate fractions


x/()+(-((x+5)*5)/()=0



We calculate terms in parentheses: +(-((x+5)*5)/(), so:

-((x+5)*5)/(

We multiply all the terms by the denominator


-((x+5)*5)



We calculate terms in parentheses: -((x+5)*5), so:

(x+5)*5

We multiply parentheses

5x+25

Back to the equation:

-(5x+25)



We get rid of parentheses

-5x-25

Back to the equation:

+(-5x-25)



We get rid of parentheses

x/()-5x-25=0

We multiply all the terms by the denominator


x-5x*()-25*()=0

We add all the numbers together, and all the variables

x-5x*()=0

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