(x+1)/5=(x+5)/7

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Solution for (x+1)/5=(x+5)/7 equation:



(x+1)/5=(x+5)/7
We move all terms to the left:
(x+1)/5-((x+5)/7)=0
We calculate fractions
x/()+(-((x+5)*5)/()=0
We calculate terms in parentheses: +(-((x+5)*5)/(), so:
-((x+5)*5)/(
We multiply all the terms by the denominator
-((x+5)*5)
We calculate terms in parentheses: -((x+5)*5), so:
(x+5)*5
We multiply parentheses
5x+25
Back to the equation:
-(5x+25)
We get rid of parentheses
-5x-25
Back to the equation:
+(-5x-25)
We get rid of parentheses
x/()-5x-25=0
We multiply all the terms by the denominator
x-5x*()-25*()=0
We add all the numbers together, and all the variables
x-5x*()=0

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