(x+1)/5=3-(x+3)/4

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Solution for (x+1)/5=3-(x+3)/4 equation: 



(x+1)/5=3-(x+3)/4

We move all terms to the left:

(x+1)/5-(3-(x+3)/4)=0

We calculate fractions


x/()+(-(3-(x+3)*5)/()=0



We calculate terms in parentheses: +(-(3-(x+3)*5)/(), so:

-(3-(x+3)*5)/(

We multiply all the terms by the denominator


-(3-(x+3)*5)



We calculate terms in parentheses: -(3-(x+3)*5), so:

3-(x+3)*5

determiningTheFunctionDomain
-(x+3)*5+3

We multiply parentheses

-5x-15+3

We add all the numbers together, and all the variables

-5x-12

Back to the equation:

-(-5x-12)



We get rid of parentheses

5x+12

Back to the equation:

+(5x+12)



We get rid of parentheses

x/()+5x+12=0

We multiply all the terms by the denominator


x+5x*()+12*()=0

We add all the numbers together, and all the variables

x+5x*()=0

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