(x+1)/5=6-(x+1)/2

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Solution for (x+1)/5=6-(x+1)/2 equation: 



(x+1)/5=6-(x+1)/2

We move all terms to the left:

(x+1)/5-(6-(x+1)/2)=0

We calculate fractions


x/()+(-(6-(x+1)*5)/()=0



We calculate terms in parentheses: +(-(6-(x+1)*5)/(), so:

-(6-(x+1)*5)/(

We multiply all the terms by the denominator


-(6-(x+1)*5)



We calculate terms in parentheses: -(6-(x+1)*5), so:

6-(x+1)*5

determiningTheFunctionDomain
-(x+1)*5+6

We multiply parentheses

-5x-5+6

We add all the numbers together, and all the variables

-5x+1

Back to the equation:

-(-5x+1)



We get rid of parentheses

5x-1

Back to the equation:

+(5x-1)



We get rid of parentheses

x/()+5x-1=0

We multiply all the terms by the denominator


x+5x*()-1*()=0

We add all the numbers together, and all the variables

x+5x*()=0

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