(x+1)/6=1-(x+3)/7

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Solution for (x+1)/6=1-(x+3)/7 equation: 



(x+1)/6=1-(x+3)/7

We move all terms to the left:

(x+1)/6-(1-(x+3)/7)=0

We calculate fractions


x/()+(-(1-(x+3)*6)/()=0



We calculate terms in parentheses: +(-(1-(x+3)*6)/(), so:

-(1-(x+3)*6)/(

We multiply all the terms by the denominator


-(1-(x+3)*6)



We calculate terms in parentheses: -(1-(x+3)*6), so:

1-(x+3)*6

determiningTheFunctionDomain
-(x+3)*6+1

We multiply parentheses

-6x-18+1

We add all the numbers together, and all the variables

-6x-17

Back to the equation:

-(-6x-17)



We get rid of parentheses

6x+17

Back to the equation:

+(6x+17)



We get rid of parentheses

x/()+6x+17=0

We multiply all the terms by the denominator


x+6x*()+17*()=0

We add all the numbers together, and all the variables

x+6x*()=0

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