(x+1)1=(x+3)(x-2)

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Solution for (x+1)1=(x+3)(x-2) equation: 



(x+1)1=(x+3)(x-2)

We move all terms to the left:

(x+1)1-((x+3)(x-2))=0

We multiply parentheses ..

-((+x^2-2x+3x-6))+(x+1)1=0



We calculate terms in parentheses: -((+x^2-2x+3x-6)), so:

(+x^2-2x+3x-6)

We get rid of parentheses

x^2-2x+3x-6

We add all the numbers together, and all the variables

x^2+x-6

Back to the equation:

-(x^2+x-6)



We get rid of parentheses

-x^2-x+(x+1)1+6=0

We add all the numbers together, and all the variables

-1x^2-1x+(x+1)1+6=0

We move all terms containing x to the left, all other terms to the right

-1x^2-1x+(x+1)1=-6

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