(x+1)2-(2x+3)2=0

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Solution for (x+1)2-(2x+3)2=0 equation:


Simplifying
(x + 1) * 2 + -1(2x + 3) * 2 = 0

Reorder the terms:
(1 + x) * 2 + -1(2x + 3) * 2 = 0

Reorder the terms for easier multiplication:
2(1 + x) + -1(2x + 3) * 2 = 0
(1 * 2 + x * 2) + -1(2x + 3) * 2 = 0
(2 + 2x) + -1(2x + 3) * 2 = 0

Reorder the terms:
2 + 2x + -1(3 + 2x) * 2 = 0

Reorder the terms for easier multiplication:
2 + 2x + -1 * 2(3 + 2x) = 0

Multiply -1 * 2
2 + 2x + -2(3 + 2x) = 0
2 + 2x + (3 * -2 + 2x * -2) = 0
2 + 2x + (-6 + -4x) = 0

Reorder the terms:
2 + -6 + 2x + -4x = 0

Combine like terms: 2 + -6 = -4
-4 + 2x + -4x = 0

Combine like terms: 2x + -4x = -2x
-4 + -2x = 0

Solving
-4 + -2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -2x = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -2x = 0 + 4
-2x = 0 + 4

Combine like terms: 0 + 4 = 4
-2x = 4

Divide each side by '-2'.
x = -2

Simplifying
x = -2

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