(x+1)3+3=3(4+2x)

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Solution for (x+1)3+3=3(4+2x) equation: 



(x+1)3+3=3(4+2x)

We move all terms to the left:

(x+1)3+3-(3(4+2x))=0

We add all the numbers together, and all the variables

(x+1)3-(3(2x+4))+3=0

We multiply parentheses

3x-(3(2x+4))+3+3=0



We calculate terms in parentheses: -(3(2x+4)), so:

3(2x+4)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

3x-(6x+12)+6=0

We get rid of parentheses

3x-6x-12+6=0

We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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